9x^2+3x-5=x=7

Solution for 9x^2+3x-5=x=7 equation:

9x^2+3x-5=x=7

We move all terms to the left:

9x^2+3x-5-(x)=0

We add all the numbers together, and all the variables

9x^2+2x-5=0

a = 9; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·9·(-5)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{46}}{2*9}=\frac{-2-2\sqrt{46}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{46}}{2*9}=\frac{-2+2\sqrt{46}}{18}
$